2x^2+105x+50=0

Solution for 2x^2+105x+50=0 equation:

2x^2+105x+50=0

a = 2; b = 105; c = +50;
Δ = b2-4ac
Δ = 1052-4·2·50
Δ = 10625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10625}=\sqrt{625*17}=\sqrt{625}*\sqrt{17}=25\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-25\sqrt{17}}{2*2}=\frac{-105-25\sqrt{17}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+25\sqrt{17}}{2*2}=\frac{-105+25\sqrt{17}}{4}
$